๐Ÿฅ‡๐Ÿฅˆ๐Ÿฅ‰

โœ‹N7 ํด๋ฆฌํŠธ๋กœํ”ฝ 1๏ธโƒฃย ์‹ค๋ฆฐ๋” ๋‚ด์— ์žˆ๋Š” ์ด์ƒ๊ธฐ์ฒด 10[kg]์„ 350[ยฐC]์ƒํƒœ์—์„œ ํด๋ฆฌํŠธ๋กœํ”ฝ ๊ณผ์ •์œผ๋กœ ์••์ถ•ํ•˜๋Š” ์ผ๋Ÿ‰์ด 900[kJ]์ด ์†Œ์š”๋˜์—ˆ์„ ๋•Œ ์—”ํŠธ๋กœํ”ผ ๋ณ€ํ™”๋Ÿ‰[kJ/K]์„ ๊ณ„์‚ฐํ•˜์‹œ์˜ค. (๋‹จ, ์ •์ ๋น„์—ด์€ 0.72[kJ/kg๏ฝฅK], ๊ธฐ์ฒด์ƒ์ˆ˜ 0.26[kJ/kg๏ฝฅK] ํด๋ฆฌํŠธ๋กœํ”ฝ ์ง€์ˆ˜ 1.3, ๋น„์—ด๋น„ 1.4์ด๋‹ค)

$$ W_a=m\times \frac{R}{n-1}\times(T_1-T_2) $$

$$ T_2=T_1-\frac{W}{m-\frac{R}{n-1}} \\ =(273-350)-\frac{900}{10\times \frac{0.26}{1.3-1}}=519.153[K] $$

$$ \Delta s=m\times C_v\times \frac{n-k}{n-1}\times \ln\frac{T_2}{T_1} $$

$$ =10\times 0.72\times \frac{1.3-1.4}{1.3-1}\times \ln\frac{519.15}{273+350}=0.437[kJ/K] $$

2๏ธโƒฃย ๋ฐœ์—ด๋Ÿ‰์ด 9030[kcal/L]์ธ ๊ฒฝ์œ  200[L]์— ๋Œ€ํ•œ TOE๋ฅผ ๊ณ„์‚ฐํ•˜์‹œ์˜ค. (๋‹จ, ๊ฒฝ์œ ์˜ ์„์œ ํ™˜์‚ฐ๊ณ„์ˆ˜[TOE/kL]๋Š” 0.905์ด๋‹ค)

$$ TOE=\frac{200}{1000}\times 0.905=0.181[TOE] $$

โœ‹I2 ์ •์••๊ณ„์‚ฐ(ํ”ผํ† ๊ด€)
3๏ธโƒฃ ๊ทธ๋ฆผ๊ณผ ๊ฐ™์€ ๊ด€๋กœ์— ๋ฒคํˆฌ๋ฆฌ๋ฏธํ„ฐ๋ฅผ ์„ค์น˜ํ•˜์—ฌ 20[ยฐC] ๋ฌผ์„ ํ†ต๊ณผ์‹œ์ผฐ์„ ๋•Œ ์˜จ๋„๊ธฐ์ค€ ํฌํ™”์ฆ๊ธฐ ํ‘œ๋ฅผ ์ฐธ๊ณ ํ•˜์—ฌ ์บ๋น„ํ…Œ์ด์…˜์ด ๋ฐœ์ƒํ•˜์ง€ ์•Š๋Š” ์กฐ๊ฑด์œผ๋กœ 2๋ฒˆ ์ง€์ ์—์„œ์˜ ์ตœ๋Œ€์œ ๋Ÿ‰[L/s]์„ ๊ณ„์‚ฐํ•˜์‹œ์˜ค.

แ„‰แ…ณแ„แ…ณแ„…แ…ตแ†ซแ„‰แ…ฃแ†บ 2023-04-18 แ„‹แ…ฉแ„’แ…ฎ 8.30.47.png

$$ A_1V_1=A_2V_2 \\ V_1=\frac{A_2}{A_1}V_2=\frac{\frac{\pi}{4}\times0.1^2}{\frac{\pi}{4}\times0.02^2}\times V_2=25V_2 $$

$$ \frac{P_1}{\rho g}+\frac{V^2_1}{2g}+z_1=\frac{P_2}{\rho g}+\frac{V^2_2}{2g}+z_2 \\ \frac{V^2_2-V^2_1}{2g}=\frac{P_1-P_2}{\rho g}+z_1 \\ \frac{V^2_2-(25V_2)^2}{2g} =\frac{V^2_2-25^2 V_2^2}{2g} =\frac{V^2_2-625V_2^2}{2g} \\ =\frac{(1-625)V_2^2}{2g}=\frac{-624V_2^2}{2g}

$$

$$ \frac{-624V_2^2}{2g}=\frac{P_1-P_2}{\rho g}+z_1 $$

$$ V_2=\sqrt{\frac{2g(\frac{P_1-P_2}{\rho g}=z_1)}{-624}}=\sqrt{\frac{2\times9.8\times(\frac{2340-120000}{1000\times9.8}+1}{-624}}=0.587[m/s] $$

$$ Q_2=A_2V_2=(\frac{\pi}{4}\times0.1^2\times0.59)\times1000=4.633[L/s] $$

แ„‰แ…ณแ„แ…ณแ„…แ…ตแ†ซแ„‰แ…ฃแ†บ 2023-04-18 แ„‹แ…ฉแ„’แ…ฎ 8.31.44.png

$$ Q_2=A_2V_2=(\frac{\pi}{4}\times 0.1^2\times 0.59)\times 1000=4.633[L/s] $$